WebIn the given figure, AD = AE and AD2 = BD x EC. Prove that: triangles ABD and CAE are similar. Solution: In Δ ABD and Δ CAE, ∠ADE = ∠AED [Angles opposite to equal sides are equal.] So, ∠ADB = ∠AEC [As ∠ADB + ∠ADE = 180 o and ∠AEC + ∠AED = 180 o ] And, AD 2 = BD x EC [Given] AD/ BD = EC/ AD AD/ BD = EC/ AE WebFind m ACD (not drawn in figure). A) 90 degrees B) 99 degrees C) 100 degrees D) 108 degrees E) 162 degrees 14. Three circles with radii of 3, 5, and x units are mutually tangent in pairs where x is the radius of the largest circle. If the lines of centers of these circles are also sides of a right triangle, then find the radius
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WebOct 16, 2024 · Then I used Geogebra to look for some results. There I found that $\angle APQ = \angle AFE$, concluding that $\Delta APQ \sim \Delta AFE$. Can anybody explain which is that so? I put $\angle AFE = (90 - x)^\circ$ and $\angle AEF = (45 + x)^\circ$, to my surprise, the results worked, but why? WebIf AB = 26 cm 2 then find DE. Solution: Question 16. If in an equilateral triangle, the length of the median is √3 cm, then find the length of the side of equilateral triangle. Solution: Short Answer Type Questions I [2 Marks] Question 17. In the figure, D andE are points on AB and AC respectively such that DE BC. If AD = 1/3 BD and AE = 4.5 ... how to link delta and hertz
In figure 1.41, if AB CD FEСthen find x and AE. - Brainly.in
WebMar 29, 2024 · In the figure if `AB CD FE` then find x and AE. WebMar 22, 2024 · Ex 6.2, 1 Deleted for CBSE Board 2024 Exams Ex 6.2, 2 Deleted for CBSE Board 2024 Exams Ex 6.2, 3 Important Deleted for CBSE Board 2024 Exams You are here Ex 6.2, 4 ... WebOct 15, 2024 · E and F are points respectively on B C and C D such that ∠ E A F = 45 ∘. A B C D is a square. E and F are points respectively on B C and C D such that ∠ E A F = 45 ∘. A E … how to link demat account to zerodha